Math Formulas
Equation Formulas
Real numbers: a,b,c,d,p,q,r,s
Solutions: $ x_{1},x_{2},y_{1},y_{2},y_{3}$
Linear Equation in One Variable
$ ax+b =0, x=-\dfrac{b}{a}$
Quadratic Equation
$ a^2+bx+c=0$ $\\$ $x_{1,2} = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} $
In Qudratic formula $(b^2- 4ac)$ is called the Discriminant, where a,b and c are real numbers, a $\neq$ 0.It is represented by D.
- When D is positive, then the roots are real and unequal.
- When D is zero, then roots are real and equal.
- When D is negative, then roots are unequal and imaginary.
- When D is positive and perfect square, then the roots are real,rational and unequal.
- When D is positive but not perfect square, then roots are real, irrational and unequal.
- When D is perfect square and a or b is irrational, then roots are irrational.
Viete's Formulas
$ p^2+qx+r=0 , \text{then} $
$\left\{
\begin{array}{l l l}
x_{1}+x_{2}=-p \\
x_{1}x_{2}=q
\end{array} \right.$
$1.~ a^2+bx=0 \\ \text{Then, } x_{1}=0,x_{2}=-\dfrac{b}{a} \\$ $2.~ a^2+c=0 \\ \text{Then, } x_{1,2}=\pm \sqrt{\dfrac{-c}{a}} \\$
Cubic Equation
$ y^3+py+q=0$
$y_{1}=r+s \ ,$
$\ y_{2,3}=-\dfrac{1}{2}(r+s) \pm \dfrac{\sqrt 3}{2}~(r-s)i \\$
$ where, \ r = \sqrt[\Large3]{-\dfrac{q}{2} + \sqrt{\left(\dfrac{q}{2}\right) ^2 + \left(\dfrac{p}{2}\right) ^3}} \\ s = \sqrt[\Large3]{-\dfrac{q}{2} + \sqrt{\left(\dfrac{q}{2}\right) ^2 - \left(\dfrac{p}{2}\right) ^3}} $